Marshall Amp & homemade speaker cabinet |
The output connections from the amplifier are the same as for the inputs: quarter inch phone jacks. We were originally just going to use a guitar cord to connect the speakers, but then I realized there is some actual power in the output, and the skinny wires in a guitar cord would not carry the load. I had some speaker wire that was pretty hefty, so we used it instead.
I got to thinking about this later and started wondering just how much current we were dealing with, so I did a little calculating. The speakers are rated at 50 watts each and have an Resistance of 8 ohms each. They are connected in parallel, so the resistance of the pair should be 4 ohms and the total power capacity should be 100 Watts. So how much electricity is flowing in these speaker wires? We start with a couple of basic formulas:
Watts = Volts x Amps
Volts = Amps x Resistance
Put 100 Watts in the first formula,
and then solve for Amps gives us: Amps = 100 / Volts.
Substituting that and Resistance = 4
into the second formula gives us: Volts = (100 / Volts) x 4
Rearranging and combining terms to
make it pretty gives us: V = 400 / V
Multiplying both sides by V gives us: V^2 = 400
Take the square root of both sides
and we end up with: V = 20
So we have 20 Volts and 100 Watts.
Put those back in the first formula
(Watts = Volts x Amps) and we have: 100 = 20 x Amps
Divide both sides by 20 and we have: 5 = Amps
So we are using 20 Volts of electricity to push 5 Amps of current through the circuit to deliver 100 Watts of Power. This is not enough current to run a toaster or a microwave, but it is enough to run five 100 Watt light bulbs, so the guitar cord, which only needs to carry a signal, which has almost no power, would have been a poor choice to use to connect the speakers.
Update October 2016 replace missing picture.
Simpler A*A*R=100; R=4, so A=5.
ReplyDeleteWell, yes, if you have memorized that formula. All I knew for sure was that volts times amps equals watts and that resistance was inversely proportional to current, and I had to look up the formula for that one to be sure.
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